Saturday, August 2, 2014

Sql Query

/* Delete Duplicate records */WITH CTE (COl1,Col2DuplicateCount)AS(SELECT COl1,Col2,ROW_NUMBER(OVER(PARTITION BY COl1,Col2 ORDER BY Col1AS DuplicateCountFROM DuplicateRcordTable)DELETE
FROM 
CTEWHERE DuplicateCount 1
GO

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SQL SERVER – 2008 – 2005 – Rebuild Every Index of All Tables of Database – Rebuild Index with FillFactor

 DECLARE @TableName VARCHAR(255)DECLARE @sql NVARCHAR(500)DECLARE @fillfactor INT
SET 
@fillfactor 80DECLARE TableCursor CURSOR FOR
SELECT 
OBJECT_SCHEMA_NAME([object_id])+'.'+name AS TableNameFROM sys.tablesOPEN TableCursorFETCH NEXT FROM TableCursor INTO @TableNameWHILE @@FETCH_STATUS 0BEGIN
SET 
@sql 'ALTER INDEX ALL ON ' @TableName ' REBUILD WITH (FILLFACTOR = ' +CONVERT(VARCHAR(3),@fillfactor) + ')'EXEC (@sql)FETCH NEXT FROM TableCursor INTO @TableNameEND
CLOSE 
TableCursorDEALLOCATE TableCursor
GO

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http://iis-7.blogspot.in/2012/09/iis-interview-questions.html
http://www.dotnetfunda.com/interviews/cat/122/iis
http://www.scribd.com/doc/94909071/IIS-Interview-Questions-and-Answers
http://www.iis.net/learn/web-hosting/frequently-asked-questions-%28faq%29/general-iis7-questions

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